Many times we come across a scenario where we need to get Date Part only from DateTime in Sql Server. There are multiple ways of doing this, here I am listing out few of them:
1) Below approach works in Sql Server 2008 and above:
SELECT CONVERT (DATE, GETDATE()) 'Date Part Only' RESULT: Date Part Only -------------- 2013-07-14
2) Below approaches works in all the versions of Sql server
i) Get Date Part only from DateTime using CONVERT function
Example 1:
SELECT CONVERT(VARCHAR(10), GETDATE(), 112) 'Date Part Only' RESULT: Date Part Only -------------- 20130714
Example 2:
SELECT CONVERT(VARCHAR(10), GETDATE(), 111) 'Date Part Only' RESULT: Date Part Only -------------- 2013/07/14
The results of the above query is of type VARCHAR, if we want the result to be of type DATETIME we can write a query like below:
Example 1:
SELECT CONVERT(DATETIME, CONVERT(VARCHAR(10), GETDATE(), 112)) 'Date Part Only' RESULT: Date Part Only ----------------------- 2013-07-14 00:00:00.000
Example 2:
SELECT CONVERT(DATETIME, CONVERT(VARCHAR(10), GETDATE(), 111)) 'Date Part Only' RESULT: Date Part Only ----------------------- 2013-07-14 00:00:00.000
ii) Get Date Part only from DateTime using DateTime functions
From performance perspective this is the better approach instead of first converting DATETIME to VARCHAR and then VARCHAR to DATETIME.
Example 1:
SELECT DATEADD(dd, 0,
DATEDIFF(dd, 0, GETDATE())) 'Date Part Only'
RESULT:
Date Part Only
-----------------------
2013-07-14 00:00:00.000
Example 2:
DECLARE @DatePartOnly DATETIME SEt @DatePartOnly = DATEDIFF(DD, 0, GETDATE()) SELECT @DatePartOnly 'Date Part Only' RESULT: Date Part Only ----------------------- 2013-07-14 00:00:00.000
iii) Get Date Part only from DateTime using FLOOR and CAST functions
As we know Sql Server internally stores DATETIME as two 4-byte integers. First 4-byte stores the elapsed number days since SQL Server’s DATETIME type’s start date 19000101.The Second 4-bytes Store the Time of Day i.e. clock-ticks since midnight. Each clock-tick is equivalent to 3.33 milliseconds.
So with above said internal storgae of the DATETIME, we can first convert the DATETIME to DECIMAL, then from decimal part ignore the fractional position and get only the integer part. Finally convert the integer to DATETIME as shown below:
SELECT CAST( -- Convert the integer to DATE
FLOOR(-- Get largest Integer less than or equal to the decimal value
CAST(GETDATE() AS DECIMAL(12, 5)) -- Convert DATETIME to DECIMAL
)
AS DATETIME) 'Date Part Only'
RESULT:
Date Part Only
-----------------------
2013-07-14 00:00:00.000
iv) Get Date Part only from DateTime using DATEPART and CONVERT functions
DECLARE @GETDATE AS DATETIME = GETDATE()
SELECT CONVERT(VARCHAR(4),DATEPART(YEAR, @GETDATE))
+ '/'+ CONVERT(VARCHAR(2),DATEPART(MONTH, @GETDATE))
+ '/' + CONVERT(VARCHAR(2),DATEPART(DAY, @GETDATE))
'Date Part Only'
RESULT:
Date Part Only
--------------
2013/7/14
You may like to read the other popular articles on Date and Time:
concept going to clear after reading.
Thanks a lot .
Keep continue….
How do you insert date into table in sql server 2012 like this:
02-01-2014 15:39
I cant find out how to get it to work?
I need it to be into on field element in the table.
when I try CURRENT_TIMESTAMP or GETDATE() I get this:
Jan 2 2014 3:40PM
I need it to be in DAY-Month-Year-Time
SELECT convert(varchar(10), getdate(), 105) + ‘ ‘ + convert(varchar(5), getdate(), 108)
What do I need to change to this to get it work:
————————————————————–
strSQL = “SELECT * FROM tablename1 order by id” + convert(varchar(10), getdate(), 105) + ” ” + convert(varchar(5), getdate(), 108),”)
And what do I need to change when I create the table from the start:
I use this:
————————————–
CREATE TABLE tablename1
(
id int NOT NULL IDENTITY(1,1),
dato varchar(255), /* Dato = the Date Coll I use*/
fornavn varchar(255),
efternavn varchar(255),
overskrift varchar(255),
indhold varchar(255),
linkoverskrift varchar(255),
link varchar(255),
PRIMARY KEY (id),
);
You query is not clear. Could you please send more detail on your requirement to basav@sqlhints.com, so that I can help you on this.
I have found the problem after some hard work Basavaraj Biradar.
It works now like this:
Select *, CONVERT(VARCHAR(10),Dato,105) + ‘ ‘ + CONVERT(VARCHAR(8),Dato,108) as timestamp from tabel
Thanks for your help.
Hi,
Do u know to change 2014-01-13 05:59:00.000 to 2014-13-01 05:59:00.000?
I tried this
left(convert(varchar(26),[CloseTime],112),4)+’-‘+RIGHT(convert(varchar(8),[CloseTime],112),2)+
‘-‘+RIGHT(convert(varchar(8),[CloseTime],112),4)+’-‘+SUBSTRING(convert(varchar(26),[CloseTime],120),10,10)
and the result is 2014-13-0113-3 05:59:00, from this how do i remove only 13-3 the bold numbers
TRY This, works in Sql 2008 and above: SELECT CAST(YEAR(GETDATE()) AS VARCHAR(4)) + ‘-‘+ CAST(DAY(GETDATE()) AS VARCHAR(2)) + ‘-‘ + CAST(MONTH(GETDATE()) AS VARCHAR(2)) +’ ‘ +CAST(CAST(GETDATE() AS TIME(3)) AS VARCHAR(12))
$final[$key][‘inner_dates’]= \DB::table(‘visit_notes’)
->select ( ‘note_id’, ‘visit_id’, ‘signed_by’, ,’save_time as date’, ‘locked’,’free_text’)
->where(‘visit_id’,@$visit_each->visit_id)
->orderBy(‘save_time’, ‘desc’)
->get();
My date is saved in time stamp I want only date my actual databse time is 2016/08/05 10:30:45 but I want only 2016/08/05 in laravel
Thank’s , could learn a lot. I loved the solution DATEADD(dd, 0,
DATEDIFF(dd, 0, GETDATE())) , convertions and string concatenations are boring, this is cool.
How can i get only year from datetime column in a table? and
is it possible to get only year from nvarchar column in a table?
Please go through the article: https://sqlhints.com/2014/02/03/how-to-get-day-month-year-and-time-part-from-datetime-in-sql-server/
hello iam looking for my column is varchar type in that iam saving date ,
now i want get seperate day , month and year from that varchar type date
or
i want to retrive order by day,month and year
all should be asc or desc
pls give me solution above qusetion
thanks
srinivas
How can i get only year from date1 datetime column in a table? and
is it possible to get only year from date1 nvarchar column in a table?
i have a problem with adding date for 10 days…
this is the case .
date format like this
2014-06-30 07:23:56.680
i want to add only day for 10 days, but the time is getdate() when i execute this query at 23:00
and result like this..
2014-07-7 23:00:00.000
can you make this one for me ?
realy confused..
thx before
Hope this will help you ……
SELECT
(CONVERT(VARCHAR(10),getdate(), 105)+’ ‘+Convert(VARCHAR(4),DATEPART(hh,GETDATE()))+”+’:00:00:00′) AS ModifiedDate
MY SQL 2005 r2
app_no app_creatdate
020900000001 2014-09-04 13:55:01.170
020900000002 2014-09-08 11:44:31.307
This is the my applications table first two columns like have so many are there in table.I want to retrive the applicantions by baSED on app_createdate
I tried with the querys like
select * from applications where app_createdate=getdate()
select * from applications WHERE date(app_createdate)=$date where $date is in 2014-09-13
and one ar more it is giving no result.
select * from applications where app_createdate>=’2014-09-13′ its working fine but giving wrong results give me excat format query.
Great site…..
Hi,
I need help in finding the last day of a month in sql 2008 r2.
data i have in a column is in YYYYMM format.
I need to use the month from this format and get the last day of that month.
please help.
Hi,
How to get the current date from the table
Where table in the formate yy-mm-dd 00.00.00.00
ALL INFO ABOUT DATE=========>>>>>>>>>>>>>
SELECT
DATEPART(year,GETDATE()) AS “year”
,DATEPART(quarter,GETDATE()) AS “quarter”
,DATENAME(month,GETDATE()) AS “month”
,DATEPART(week,GETDATE()) AS “week”
,DATEPART(dayofyear,GETDATE()) AS “dayofyear”
,DATENAME(weekday,GETDATE()) AS “weekday”
,DATEPART(weekday,GETDATE()) AS “weekday#”
,DATEPART(day,GETDATE()) AS “day”
ALL INFO ABOUT CURRENT TIME—————>>>>>>>>>>>>
SELECT
— TIME PARTS
DATEPART(HOUR,SYSDATETIME()) AS “hour”
,DATEPART(MINUTE,SYSDATETIME()) AS “minute”
,DATEPART(SECOND,SYSDATETIME()) AS “second”
,DATEPART(MILLISECOND,SYSDATETIME()) AS “millisecond”
,DATEPART(MICROSECOND,SYSDATETIME()) AS “microsecond”
,DATEPART(NANOSECOND,SYSDATETIME()) AS “nonosecond”
hello all,,
how to separate date from datetime ,the datetime column should be retrieved from database .
thanks in advance
SET @varDiaDoAtend = (DATEPART(DAY,@varDataDoAtend));
SET @varMesDoAtend = (DATEPART(MONTH,@varDataDoAtend));
SET @varDataDoAtendFormatada = (@varDiaDoAtend + ‘/’ + @varMesDoAtend);
NOW JUST ADD YEAR